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Update units.rst

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In LJ units, the conversion formula between rho and rho* should be corrected to   
\rho^* = \rho \frac{\sigma^{dim}}{m}
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Bhanuday Sharma
2021-03-31 06:44:52 +05:30
committed by GitHub
parent 180d2895c4
commit 7092a7769c
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doc/src/units.rst
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@ -87,7 +87,7 @@ energy is a derived unit (in SI units you equivalently have the relation
* charge = reduced LJ charge, where :math:`q^* = q \frac{1}{\sqrt{4 \pi \varepsilon_0 \sigma \epsilon}}` * charge = reduced LJ charge, where :math:`q^* = q \frac{1}{\sqrt{4 \pi \varepsilon_0 \sigma \epsilon}}`
* dipole = reduced LJ dipole, moment where :math:`\mu^* = \mu \frac{1}{\sqrt{4 \pi \varepsilon_0 \sigma^3 \epsilon}}` * dipole = reduced LJ dipole, moment where :math:`\mu^* = \mu \frac{1}{\sqrt{4 \pi \varepsilon_0 \sigma^3 \epsilon}}`
* electric field = force/charge, where :math:`E^* = E \frac{\sqrt{4 \pi \varepsilon_0 \sigma \epsilon} \sigma}{\epsilon}` * electric field = force/charge, where :math:`E^* = E \frac{\sqrt{4 \pi \varepsilon_0 \sigma \epsilon} \sigma}{\epsilon}`
* density = mass/volume, where :math:`\rho^* = \rho \sigma^{dim}` * density = mass/volume, where :math:`\rho^* = \rho \frac{\sigma^{dim}}{m}`
Note that for LJ units, the default mode of thermodynamic output via Note that for LJ units, the default mode of thermodynamic output via
the :doc:`thermo_style <thermo_style>` command is to normalize all the :doc:`thermo_style <thermo_style>` command is to normalize all